Procrastinating and problems..

EDIT 11/28/2012 6:00PM : WHEN WRITING THIS POST, FOR SOME REASON, I THOUGHT THE HOMEWORK WAS DUE THE NEXT DAY. FOR THE SAKE OF THE POST LET'S JUST PRETEND IT WAS.
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So I just got done with my math homework tonight. Although I am a horrible procrastinator, or awesome procrastinator depending on how you look at it, I usually spread my online math homework out well over the section. This is due to the fact that I have a 2 hour break between classes. However, even with a 2 hour break, my all too familiar procrastination crept in. The math homework for other chapters hasn't been too difficult, so I figured I could knock out most of it fairly quickly. Boy was I wrong. As luck has it, the section in which I decided to do the homework last minute has proved to be the most difficult for me yet.

One of the biggest problems I ran into was the fact that I did not know all the formulas by memory. There were many different formulas used for the many different shapes and calculations. I found myself having to work through the examples on many of the problems. This was very time consuming. I am glad we have access to these types resources when doing our homework. Otherwise, I probably would have just skipped many problems altogether.

The following is one of the problems in which I had to work through the example to solve:

A right cylindrical can is to hold 1 L of water. What should be the height of the can if the radius is 9cm? Use 3.14159 for π.

The first thing you do is convert your L into cm. 1 L = 1000cm³.

Next you set your 1000cm³ equal to the volume of a cylinder.

1000cm³ = πr²h

Then you plug in your numbers and solve for h.

1000cm³ ≈ 3.14159(9)²h

h ≈ 3.93cm